SQL Server MTRIL Function
Updated 2023-10-17 14:29:36.847000
Description
Use the scalar function MTRIL to return the lower triangular part of the string representation of a matrix.
MTRIL expects a string representation of the matrix, with columns separated by commas and rows separated by semi-colons.
Syntax
SELECT [westclintech].[wct].[MTRIL](
<@Matrix, nvarchar(max),>)
Arguments
@Matrix
a string representation of a matrix.
Return Type
nvarchar(max)
Remarks
The string representations of @Matrix must only contain numbers, commas (to separate the columns), and semi-colons to separate the rows.
Consecutive commas will generate an error.
Consecutive semi-colons will generate an error.
Non-numeric data between commas will generate an error
Non-number data between semi-colons will generate an error
To convert non-normalized data to a string format, use the Matrix2String or the Matrix2String_q function.
To convert normalized data to a string format, use the NMatrix2String or the NMatrix2String_q function.
Examples
Let's assume that we had the following matrix, A, and we want to return the lower triangular part.
A = [-79,-45,9,9,-91,-5;68,46,9,81,-61,35;83,-25,80,-67,-22,-38;77,40,-24,69,73,-20;-17,-72,-9,-72,-6,-34;64,-47,48,-54,18,11;-4,-36,7,-56,-34,-3;-41,90,78,-43,38,64;-60,-85,-31,-83,-96,-36;-40,31,-93,-62,64,10]
We could enter the following SQL to perform the calculation.
DECLARE @A as varchar(max);
SET @A
= '-79,-45,9,9,-91,-5;68,46,9,81,-61,35;83,-25,80,-67,-22,-38;77,40,-24,69,73,
-20;-17,-72,-9,-72,-6,-34;64,-47,48,-54,18,11;-4,-36,7,-56,-34,-3;
-41,90,78,-43,38,64;-60,-85,-31,-83,-96,-36;-40,31,-93,-62,64,10';
SELECT wct.MTRIL(@A) as [L];
This produces the following result.
| L |
|---|
| -79,0,0,0,0,0;68,46,0,0,0,0;83,-25,80,0,0,0;77,40,-24,69,0,0;-17,-72,-9,-72,-6,0;64,-47,48,-54,18,11;-4,-36,7,-56,-34,-3;-41,90,78,-43,38,64;-60,-85,-31,-83,-96,-36;-40,31,-93,-62,64,10 |
Of course, this is a little hard to read. Since the result is a string, we can reformat the solution to make it easier to read. Simply by changing the SELECT statement:
SELECT item
FROM wct.SPLIT(wct.MTRIL(@A), ';') l;
This produces the following result.
| item |
|---|
| -79,0,0,0,0,0 |
| 68,46,0,0,0,0 |
| 83,-25,80,0,0,0 |
| 77,40,-24,69,0,0 |
| -17,-72,-9,-72,-6,0 |
| 64,-47,48,-54,18,11 |
| -4,-36,7,-56,-34,-3 |
| -41,90,78,-43,38,64 |
| -60,-85,-31,-83,-96,-36 |
| -40,31,-93,-62,64,10 |
Which is a little bit easier to follow
However, we can use the table-valued function MATRIX, to format the result in third-normal form where it is even easier to see the output.
SELECT *
FROM wct.MATRIX(wct.MTRIL(@A)) l;
This produces the following result.
| RowNum | ColNum | ItemValue |
|---|---|---|
| 0 | 0 | -79 |
| 0 | 1 | 0 |
| 0 | 2 | 0 |
| 0 | 3 | 0 |
| 0 | 4 | 0 |
| 0 | 5 | 0 |
| 1 | 0 | 68 |
| 1 | 1 | 46 |
| 1 | 2 | 0 |
| 1 | 3 | 0 |
| 1 | 4 | 0 |
| 1 | 5 | 0 |
| 2 | 0 | 83 |
| 2 | 1 | -25 |
| 2 | 2 | 80 |
| 2 | 3 | 0 |
| 2 | 4 | 0 |
| 2 | 5 | 0 |
| 3 | 0 | 77 |
| 3 | 1 | 40 |
| 3 | 2 | -24 |
| 3 | 3 | 69 |
| 3 | 4 | 0 |
| 3 | 5 | 0 |
| 4 | 0 | -17 |
| 4 | 1 | -72 |
| 4 | 2 | -9 |
| 4 | 3 | -72 |
| 4 | 4 | -6 |
| 4 | 5 | 0 |
| 5 | 0 | 64 |
| 5 | 1 | -47 |
| 5 | 2 | 48 |
| 5 | 3 | -54 |
| 5 | 4 | 18 |
| 5 | 5 | 11 |
| 6 | 0 | -4 |
| 6 | 1 | -36 |
| 6 | 2 | 7 |
| 6 | 3 | -56 |
| 6 | 4 | -34 |
| 6 | 5 | -3 |
| 7 | 0 | -41 |
| 7 | 1 | 90 |
| 7 | 2 | 78 |
| 7 | 3 | -43 |
| 7 | 4 | 38 |
| 7 | 5 | 64 |
| 8 | 0 | -60 |
| 8 | 1 | -85 |
| 8 | 2 | -31 |
| 8 | 3 | -83 |
| 8 | 4 | -96 |
| 8 | 5 | -36 |
| 9 | 0 | -40 |
| 9 | 1 | 31 |
| 9 | 2 | -93 |
| 9 | 3 | -62 |
| 9 | 4 | 64 |
| 9 | 5 | 10 |
And, if we wanted to see the result in a row/column presentation, we could use the following SQL.
SELECT [0],
[1],
[2],
[3],
[4],
[5]
FROM
(SELECT * FROM wct.MATRIX(wct.MTRIL(@A)) ) M
PIVOT
(
MAX(ItemValue)
FOR colnum IN ([0], [1], [2], [3], [4], [5])
) AS pvt
ORDER BY rownum;
This produces the following result.
| 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| -79 | 0 | 0 | 0 | 0 | 0 |
| 68 | 46 | 0 | 0 | 0 | 0 |
| 83 | -25 | 80 | 0 | 0 | 0 |
| 77 | 40 | -24 | 69 | 0 | 0 |
| -17 | -72 | -9 | -72 | -6 | 0 |
| 64 | -47 | 48 | -54 | 18 | 11 |
| -4 | -36 | 7 | -56 | -34 | -3 |
| -41 | 90 | 78 | -43 | 38 | 64 |
| -60 | -85 | -31 | -83 | -96 | -36 |
| -40 | 31 | -93 | -62 | 64 | 10 |
In this example, we insert the matrix values into a table, #m, which is in ‘spreadsheet' format, and we use the MATRIX2STRING function to convert the table values into a string format to be used by the MTRIL function.
SELECT *
INTO #m
FROM (
SELECT -79,-45, 9, 9,-91, -5 UNION ALL
SELECT 68, 46, 9, 81,-61, 35 UNION ALL
SELECT 83,-25, 80,-67,-22,-38 UNION ALL
SELECT 77, 40,-24, 69, 73,-20 UNION ALL
SELECT -17,-72, -9,-72, -6,-34 UNION ALL
SELECT 64,-47, 48,-54, 18, 11 UNION ALL
SELECT -4,-36, 7,-56,-34, -3 UNION ALL
SELECT -41, 90, 78,-43, 38, 64 UNION ALL
SELECT -60,-85,-31,-83,-96,-36 UNION ALL
SELECT -40, 31,-93,-62, 64, 10
) n(x0,x1,x2,x3,x4,x5);
SELECT [0],[1],[2],[3],[4],[5]
FROM (
SELECT *
FROM wct.MATRIX((SELECT wct.MTRIL(wct.MATRIX2STRING('#m','*','',NULL))))
) M PIVOT(
MAX(ItemValue)
FOR colnum IN([0],[1],[2],[3],[4],[5])
) AS pvt
ORDER BY rownum;
This produces the following result.
| 0 | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| -79 | 0 | 0 | 0 | 0 | 0 |
| 68 | 46 | 0 | 0 | 0 | 0 |
| 83 | -25 | 80 | 0 | 0 | 0 |
| 77 | 40 | -24 | 69 | 0 | 0 |
| -17 | -72 | -9 | -72 | -6 | 0 |
| 64 | -47 | 48 | -54 | 18 | 11 |
| -4 | -36 | 7 | -56 | -34 | -3 |
| -41 | 90 | 78 | -43 | 38 | 64 |
| -60 | -85 | -31 | -83 | -96 | -36 |
| -40 | 31 | -93 | -62 | 64 | 10 |